pyoneall config site_name

Carlos_Catucci

Hi people

I'm trying to use the pyoneall module to connect, but isn't clear for me what kind of value I must put in the key ite_name.

I've try with the site url, and with the https://SITENAME.api.oneall.com that i've definedn when I've create the site, but I ot back the follow stacktrace error when I invoke connections = oa.connections()

Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/home/globex/server/lib/python2.7/site-packages/pyoneall/connection.py", line 119, in connections connections = self._paginated('connections', 'connections', page_number, last_page, fetch_all, rtype=Connections) File "/home/globex/server/lib/python2.7/site-packages/pyoneall/connection.py", line 60, in _paginated response = OADict(**self._exec(action, {'page' : page_number})).response File "/home/globex/server/lib/python2.7/site-packages/pyoneall/connection.py", line 42, in _exec return loads(urlopen(req).read()) File "/usr/lib/python2.7/urllib2.py", line 127, in urlopen return _opener.open(url, data, timeout) File "/usr/lib/python2.7/urllib2.py", line 404, in open response = self._open(req, data) File "/usr/lib/python2.7/urllib2.py", line 422, in _open '_open', req) File "/usr/lib/python2.7/urllib2.py", line 382, in _call_chain result = func(*args) File "/usr/lib/python2.7/urllib2.py", line 1222, in https_open return self.do_open(httplib.HTTPSConnection, req) File "/usr/lib/python2.7/urllib2.py", line 1184, in do_open raise URLError(err) urllib2.URLError: <urlopen error [Errno -2] Name or service not known>

The urlopen error implies that the siste:_name isn't correct, but I coudn't understand what value he waiting for.

Thank's a lot

Carlos

Claude_Schlesser

Hi Carlos,

you first need to create a New Site in your OneAll account: https://app.oneall.com/
Then you go to the Dashboard of that site.

The SITENAME corresponds to the Subdomain.

Regards,

Carlos_Catucci

Perfect, i've tried it and appera to go but our confirmation it's a good thing