identity_token = connection_token?

After I connect to a social network using oneall, I get a javacsript redirect event with a user_token, and a connection object with a connection_token.
Your API documentation talks about an identity_token and I wonder if the connection_token is the identity_token?
If not, then how can I obtain the identity_token?

Also, you have code samples on the REST API for PHP and Java, however I would like to see javascript sample code also.

Best Answer

  • Fred_PinelFred_PinelMember
    Answer ✓
    Hi,
    An identity token points to an identity record for the user: a social network identity for the user.
    The user may have different identities, one per social network. Querying the user token will give you the identities we know about.

    Hope this helps.

Answers

  • I figured this out. The connection_token should be sent to our own Web API and used with the API key and secret key as Basic Authorisation to GET from "https://trisys.api.oneall.com/connections/" + connection_token + ".json";
    This file stream contains all of the logged in user details.
    You cannot query the oneall.com ReST API from JS in the browser as you will encounter CORS errors.
  • My site is broken:

    https://trisys.api.oneall.com/

    {"response":{"request":{"date":"Wed, 17 Apr 2019 17:23:18 +0200","resource":"\/","status":{"flag":"error","code":404,"info":"We are really sorry, but the resource you are trying to access does not exist. If you are currently implementing our services, then please make sure that your callback_uri points to a file on your server and not on ours."}}}}

  • Claude_SchlesserClaude_SchlesserAdministratorOneAll Team
    edited April 2019

    Hi Garry,

    the root subdomain (in your case https://trisys.api.oneall.com/) is not useable as such. I can however confirm that the subdomain trisys exists.

    Based on the error message I would case that the callback_uri in your JavaScript is pointing to that URL. Could you post the link to the page where I can reproduce the error?

    Regards,

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